By Roger Freedman ,Todd Ruskell ,Philip R. Kesten

ISBN-10: 1464135622

ISBN-13: 9781464135620

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20 m/s2. To determine whether or not the trains collide, we can 52 Chapter 2 Linear Motion calculate the stopping distance required for each train, add them together, and see if it is less than 300 m. If so, the trains are safe; if not, the trains crash. We know the trains’ initial speeds, final speeds, and acceleration, and we are interested in finding the distance, which suggests we use v 2x 5 v 20x 1 2ax 1 x 2 x0 2 . 20 2 b s Total distance required to stop both trains: 106 m 1 132 m 5 238 m.

5 km 2 . The two positions are equal to one another when the car h overtakes the truck. Solving for t will give the time it takes for the car to reach the truck. 00 s to hit the brakes. 0 km/h. 0 km/h before hitting the brakes. We can use the definition of average speed to calculate the extra distance the drunk driver travels. 0 m Η h 3600 s 1 km Reflect The impaired driver travels an extra distance of over 55 ft before applying the brakes. 44 Set Up A jet travels 3000 km from San Francisco to Chicago.

0 km/h when the traffic signal changes from green to yellow. 750 s before hitting the brake. 50 m/s2 until it stops. The distance the car travels during this process can be split into two parts: the distance traveled before the brake is applied and the distance traveled after the brake is applied. 750 s. While the brake is applied, the car is undergoing constant acceleration so the equation v 2x 5 v 20x 1 2ax 1 x 2 x0 2 can be used to calculate the distance. The minimum distance necessary to come to a stop is the sum of these two.

### Instructor's Solution Manuals to College Physics by Roger Freedman ,Todd Ruskell ,Philip R. Kesten

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